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Likurg_2 [28]
2 years ago
11

A right cylinder has a circumference of 16 π cm . Its height is half the radius. Identify the lateral area and the surface area

of the cylinder.
Mathematics
1 answer:
Wittaler [7]2 years ago
4 0

The lateral area is 32π  sqcm and the surface area of the cylinder is 4096π² sqcm.

<h3>What is a right cylinder?</h3>

A right cylinder is a cylinder whose sides are perpendicular to its base.

It is given that-.

circumference of cylinder = 16 π cm

Suppose, r is radius of the cylinder,

h is height of the cylinder.

Then,

⇒ 2 π r = 16 π

⇒ r = 8 cm.

It is also given that,

height = 1/2radius

⇒ h = 1/2r

⇒ h = 1/2 * 8 cm

⇒ h = 4 cm

Now,∵ lateral area of cylinder =  2 π r h

∴ lateral area of cylinder =  16*  π * 4

⇒ lateral area of cylinder = 32π  sqcm.

Similarly, surface area of the cylinder  =  2 π r h * 2 π r²

⇒ surface area of the cylinder  =  2 π r h * 2 π (8)²

⇒ surface area of the cylinder  =  32π * 2 π 64

⇒ surface area of the cylinder  =  4096 * π² sqcm

Hence,the lateral area is 32π  sqcm and the surface area of the cylinder is 4096π² sqcm.

More about Right Cylinder :

brainly.com/question/16224398

#SPJ1

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A rectangular parcel of land has an area of 6,000 ft2. A diagonal between opposite corners is measured to be 10 ft longer than o
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Answer:

50ft by 120ft

Step-by-step explanation:

Area of a rectangle = L × W

6000ft² = L × W

L = 6000/W

When a diagonal line divides a rectangle into 2 right angled triangles, the diagonal line = Hypotenuse of either of the triangle and it is the longest side.

The formula for a right angle triangle =

a² + b² = c²( c = hypotenuse)

We are told in the question that:

A diagonal between opposite corners is measured to be 10 ft longer than one side of the parcel

Let us assume the side that the hypotenuse is longer than = Width

Hence, the Diagonal = (W + 10)²

Therefore

L² + W² = (W + 10)²

Since L = 6000/W

W² + (6000/W)² = (W + 10)²

W² + (6000/W)² = (W + 10) (W + 10)

W² + (6000/W)² = W² + 10W + 10W + 100

W² + (6000/W)² = W² + 20W + 100

W² - W² + (6000/W)² = 20W+ 100

6000²/W² = 20W + 100

6000² = W²( 20W + 100)

6000² = 20W³ + 100W²

20W³ + 100W² - 6000² = 0

20W³ + 100W² - 36000000 = 0

20(W³ + 5W² - 1800000) = 0

Factorising the quadratic equation,

20(W − 120)(W² + 125W + 15000) = 0

W - 120 = 0

W = 120

Therefore,

W(Width) = 120feet

Since the Width = 120 feet

We can find the length

6000ft² = L × W

L = 6000/W

L = 6000/120

L = 50 feet

The dimensions of the land, correct to the nearest foot is 50ft by 120ft

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3 years ago
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