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Naddik [55]
2 years ago
13

Given the angles inscribed in the circle, find m ∠ DBC.

Mathematics
2 answers:
Cloud [144]2 years ago
6 0

Answer:

m∠DBC = 51°

Step-by-step explanation:

<u>Circle Theorem vocabulary</u>

  • Chord: A straight line joining two points on the circle.
  • Inscribed angle: The angle formed when two chords meet at one point on a circle.
  • Intercepted arc: The arc that is between the endpoints of the chords that form the inscribed angle.

<u>Inscribed Angle Theorem</u>

The measure of an <u>inscribed angle</u> is half the measure of the <u>intercepted arc</u>.

Therefore:

\sf \implies \angle DBC=\dfrac{1}{2}\:\overset{\frown}{BC}

\sf \implies \angle DBC=\dfrac{1}{2}\:(102^{\circ})

\sf \implies \angle DBC=51^{\circ}

Learn more about the Inscribed Angle Theorem here:

brainly.com/question/27934538

brainly.com/question/27943630

ASHA 777 [7]2 years ago
5 0

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

To determine ∠DBC, we will apply the theorem relating the inscribed angle to the intercepted arc:

\longrightarrow \sf{Intercepted \: arc= (inscribe \: angle)}

\longrightarrow \sf{Intercept \: arc= 102^\circ}

\longrightarrow \sf{Inscribed \: angle= \angle DBC }

\longrightarrow \sf{102=2( \angle DBC)}

\longrightarrow \sf{\angle DBC= \dfrac{102}{2} }

▪ \longrightarrow \sf{\angle DBC = 51^\circ}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\boxed{\bf{\large m \: \angle DBC= 51^\circ}}

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while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D
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\bold{\huge{\orange{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • <u>While </u><u>shopping </u><u>for </u><u>clothes </u><u>Tracey </u><u>spent </u><u>3</u><u>8</u><u>$</u><u> </u><u>less </u><u>than </u><u>3</u><u> </u><u>times </u><u>of </u><u>what </u><u>Daniel </u><u>spent </u>

\bold{\underline{ To\: Find :- }}

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x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

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x^2 = \dfrac{25 \times 54^2}{24}

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x =\dfrac{5 \times 54}{\sqrt{24}}

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