Ask question

Ask question

All categories

3 years ago

7

PLS HELP!!!!! What are the zeros of polynomial function

0%2B%2016" id="TexFormula1" title="F(x) = x^4 - 10x^2 + 16" alt="F(x) = x^4 - 10x^2 + 16" align="absmiddle" class="latex-formula">

1 answer:

mina [271]3 years ago

6 0

Answer:

heres the answer, in the screenshot.

You might be interested in

Find the distance between the pair of points.<br> (2,3) and (6,7)

photoshop1234 [79]

Answer:

6.4

Step-by-step explanation:

formula: √(X2-X1)²+(Y2-Y1)²

hope it helps!

8 0

3 years ago

Read 2 more answers

Help me pls i dont understand math

e-lub [12.9K]

Answer:

c = -6

Step-by-step explanation:

Let us solve your equation step-by-step, which is this: c /−3 + 5 = 7

The first step is to simplify both sides of the equation: −1 /3 c + 5 = 7

Then, subtract 5 from both sides: -1/3c + 5 - 5 = 7 - 5 ---> -1/3c = 2

Multiply both sides by -3/1 making it equal to: c = -6.

4 0

3 years ago

Plz help I’ll mark you

timurjin [86]

Answer:

A 1/2

Step-by-step explanation:

Ratio of short length to hypotenuse

= cos60

= 1/2

4 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

Help quickly as possible thank you :)

Stells [14]

Answer:

50/100 and .50

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers