Answer: options b and c
<u>Step-by-step explanation:</u>
∠ACD is supplementary to ∠ACE <em>given</em>
∠ACD is supplementary to ∠BCD <em>given</em>
⇒ ∠ACE is supplementary to ∠BCD <em>transitive property</em>
∠ACD ≅ ∠BCE <em>given</em>
⇒ ∠BCE is supplementary to ∠ACE <em>substitution</em>
and ∠BCE is supplementary to ∠BCD <em>substitution</em>
********************************************************************************
multiple choice options:
a) ∠ACE is supplementary to ∠BCD <em>False</em>
b) ∠BCE is supplementary to ∠ACE <em>TRUE</em>
c) ∠BCD is supplementary to ∠BCE <em>TRUE</em>
d) ∠ACE ≅ ∠BCE <em> False</em>
e) ∠BCD ≅ ∠ACE <em>False</em>
Answer:
71s
Step-by-step explanation:
The question we have at hand is 7s² + ___ + 13s + 6² = (7s + 6)². We can expand the perfect equation " (7s + 6)² " in order to find our solution. A perfect square consists of 3 terms, and hence the term in the blanks must add to 13s to form another term.
Applying the perfect square formula : ( a + b )² = a² + 2ab + b², let's expand the expression,
(7s + 6)² = ( 7s )² + 2( 7s )( 6 ) + ( 6 )² = 7s² + 84s + 6²
84s - 13s = 71s, which fills in the blank provided.
T<span>he mean of a sampling distribution of a sample with proportion, p and sample size, n is given by

.
</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by

</span>Given that t<span>he
manufacturers of m&m's claim that 20% of the milk chocolate m&m
candies are orange. The proportion is p = 0.2
The mean of the
sampling distribution of the sample proportion of orange m&m's for
samples of size 100 is given by

</span><span>The standard deviation of the
sampling distribution of the sample proportion of orange m&m's for
samples of size 100 is given by

</span>
Answer:
Tags not given out=(k/5)-40
Step-by-step explanation:
k is tag
Tags k given to student are half = k/2
Tags given to parents are= 100
Total tags given to students and parents are=(k/2)+100
So remaining tags are=k-(k/2+100)
=(k-200)/2
tags given to judges and teacher are 3/5 of remaining tags =(3/5)*((k-200)/2)
So tags not given out are =(2/5)*((k-200)/2)
=(k/5)-40 Answer
If the line has a positive slope and a negative y-intercept, then the <span>points cannot lie on the line where x is negative and y is positive. The points never lie at quadrant 1. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>