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Ahat [919]
2 years ago
5

Given these facts, determine how many cans of paint you would need to buy to paint 2 walls.

Mathematics
1 answer:
Tatiana [17]2 years ago
5 0

Answer:

3 cans

Step-by-step explanation:

A = lw

a = 20 x 8 = 160ft^{2}

a = 40 x 8 = 320 ft^{2}

Together this is 480 ft^{2}

I would need 3 cans.

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Can someone help me on this question
andre [41]

Answer:

The answer is about 32,000.

Step-by-step explanation:

If you multiply 3.2 by 10, for 10 years, you get 32 percent. From there, if you multiply 25,000 by 0.32, you get 8000. If you add 25,000 to 8000, you get about 32,000.

5 0
4 years ago
PART A: A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the tr
Greeley [361]

Complete Question:

Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.  

(b) Determine the scale factor from the first map to the second map.

(c)  A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?  

(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:

Answer:

(a) Length = 4cm

(b) Scale factor = 0.5

(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

Length =4cm <em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>

(b) The scale factor

The scale factor (k) is calculated as:

k = \frac{New\ Length}{Old\ Length}

k = \frac{4cm}{8cm}\\

k = 0.5

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

k = \frac{New\ Length}{Old\ Length}

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

New\ Length = k * Old\ Length

When Length = 3cm

New\ Length = 0.5 * 3cm = 1.5cm

When Length = 4cm

New\ Length = 0.5 * 4cm = 2cm

When Length = 5cm

New\ Length = 0.5 * 5cm = 2.5cm

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

7 0
3 years ago
I need help please. The question is already there. Tysm. 20 points.
Bess [88]

Answer:

$109 and 35%

Step-by-step explanation:

49.05 is the sale price and the discount is 55%. What’s the original price?

price/ 1- discount

49.05/ 1 - 0.55

49.05/ 0.45

109

for the other part

to find the discount subtract final price from original price

94 - 61.10 = 32.9

Which would be 35% in percent form.

5 0
3 years ago
HELP!! Triangle A′B′C′ is the image of triangle ABC after a dilation.
Nina [5.8K]
Down three and over left four so something like (-3, -4) im pretty sure
3 0
3 years ago
(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +
jekas [21]

Answer:

1. The slope of the line is m=\frac{-2b+3}{2a}.

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

m=\frac{-b-(b-3)}{a+3-(-a+3)}

m=\frac{-b-b+3}{a+3+a-3)}

m=\frac{-2b+3}{2a}

The slope of the line is m=\frac{-2b+3}{2a}.

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

m_1=\frac{5-1}{6-a}=\frac{4}{6-a}

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}

The slopes of two parallel lines are same.

m_1=m_2

\frac{4}{6-a}=\frac{-6}{a}

On cross multiplication we get

4a=-6(6-a)

4a=-36+6a

4a-6a=-36

-2a=-36

Divide both sides by -2.

a=18

Therefore the value of a is 18.

8 0
3 years ago
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