Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.
Explanation:
From the given information,
Initial population = 1000
Increasing rate or growth rate = 30% every hour.
No of population increase in every hour is,
Total population after h hours is,
It is in the form of,
Where 
is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex] is the growth factor after time t.
In the above equation 1000 is the initial population and 
is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.
Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.
Answer:
12x⁴y⁴
Step-by-step explanation:
3xy + 3xy + 3xy + 3xy = 12x⁴y⁴
Answer:
Now we can calculate the p value. Since is a bilateral test the p value would be:
Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%
Step-by-step explanation:
Information given
n=900 represent the random sample selected
estimated proportion of residents favored annexation
is the value that we want to test
represent the significance level
z would represent the statistic
represent the p value
Hypothesis to test
The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:
Null hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
(1)
Replacing the data given we got:
Now we can calculate the p value. Since is a bilateral test the p value would be:
Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%
The formula of the future value of annuity ordinary
Fv=pmt [(1+r)^(n)-1)÷r]
Fv future value
Pmt payment per year 4000
R interest rate 0.0215
N time 5 years
Fv=4,000×(((1+0.0215)^(5)−1)÷(0.0215))
fv=20,878.69
