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1 year ago

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Darlene is building a rectangular fence. the length is 8 feet longer than the width. the perimeter of the rectangle is 76 feet.

what is the length of the rectangle?

1 answer:

Llana [10]1 year ago

4 0

Answer:8 feet

Step-by-step explanation:

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A clothing store has a going-out-of business sale. They are selling pants for $8.99 and shirts for $3.99. You can spend as much

astraxan [27]

Answer:

Let x represents the number of pants and y represents the number of shirts.

As per the statement:

Since, a clothing store are selling pants for $8.99 and shirts for $3.99

then;

total number of Pants cost is, $8.99x and total number of Shirt cost is, $3.99

Also, it is given that: You can spend as much as $60 and want to buy at least two pairs of pants.

then, we have the equation of inequality;

$8.99x + 3.99y \leq 60$ ;......[1] where x, y are natural number.

x-intercept:

Substitute the value y= 0 in [1] and solve for x;

$8.99x + 3.99(0) \leq 60$

$8.99x \leq 60$

Simplify:

$x \leq 6.667$

Since, x is in natural number;

$x \leq 7$

Similarly.

For y-intercept:

Substitute the value x= 0 in [1] and solve for x;

$8.99(0) + 3.99y \leq 60$

$3.99y \leq 60$

Simplify:

$y \leq 15.037$

$y \leq 15$

Therefore, we have

$8.99x + 3.99y \leq 60$ ;

$2\leq x\leq 7$ and $0\leq y\leq 15$

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3 years ago

Help me with math please

Firdavs [7]

Answer is A..... hope it helps

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3 years ago

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Dale made a scale drawing of a house and its lot. The scale he used was 1 inch: 7 feet. The actual length of the backyard is 35

Kipish [7]

Answer:

5

Step-by-step explanation:

<em>35/7=5 </em>

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3 years ago

What is a expression that contains at least one variable

NeX [460]

4x (-2s+4x^2)
is an multiplication expression

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3 years ago

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(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s

Bezzdna [24]

(i) Since P(t) gives the population of the culture after t seconds, the population after 1 second is

P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

(P(6) - P(2))/(6 - 2) ≈ 321.030

In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

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2 years ago