Answer:
f(x)=8*(3.5)^x
Step-by-step explanation:
2=98
3= 98r
4= 98r^2
5= 98r^3
6= 98r^4
98r^4/98, 98 crosses out and its just r^4. r^4= 14706.125/98
r=3.5
So you plug that in and you get f(x)=8*(3.5)^x
I hope this helped. XD
i try my best to find the answer and then i will tell just give me some time
48
-2(1)^2(3(1)^2 – 7(1) + 10)
-2^2(3^2 – 7 + 10)
4(9 - 7 + 10)
4(12)
The required probability is
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that,
Probability for first draw to be non-defective
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective
(printers after first slot = 10; total defective printers = 2)
Then, total probability
The answer is 3x because 3 times 4 is 12, and 12+3=15.