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Natali [406]
1 year ago
8

Please help i will give brainliest

Mathematics
1 answer:
nexus9112 [7]1 year ago
8 0

Answer: y = 8x + 20

Step-by-step explanation: each cd costs 8 so headset cost 20.

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Nagayama writes one check for $459 to buy a lawnmower and another check for $32 to buy a hedge
sladkih [1.3K]

Answer:

565.24

Step-by-step explanation:

1056.24-459-32=565.24

4 0
3 years ago
Read 2 more answers
Please help me with this
Sati [7]

Answer:

x = \sqrt{11.4^2+2.6^2}\\\\

Rounded to the nearest hundredths: 11.69.

Step-by-step explanation:

I would use the Pythagorean theorem for this problem.

The difference between the highest point and the lowest point of AD is 9.8-7.2 = 2.6, so that would be the height of the triangle. The length/base of the triangle would be 11.4.

Now, just solve using Pythagorean's theorem:

x = \sqrt{11.4^2+2.6^2}\\\\

Rounded to the nearest hundredths: 11.69.

I hope this helped you.

5 0
3 years ago
Find all solutions to the equation
UNO [17]
\bold{FULL ANSWERS:}

8 0
1 year ago
All factors for 3,235?
natali 33 [55]

Answer:

1,5,647,3235

Step-by-step explanation:

there yah go

6 0
3 years ago
The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

So, the hypotenuse decreases H - H' \approx 17 - 14.3 = 2.7

3 0
3 years ago
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