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ZanzabumX [31]
3 years ago
10

My dog, Petey weighs 75 pounds. Last summer he weighed 65 pounds. What percent of his weight did he gain?

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

he gain 10%

Step-by-step explanation:

Margaret [11]3 years ago
7 0

Answer:

He gained <u>10 lbs</u> which is <u>13.3 % of 75</u>

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The price of a cup of coffee was $2.65 yesterday. Today, the price fell to $2.30 . Find the percentage decrease. Round your answ
Semenov [28]
Percent change = change/original * 100
(2.65 - 2.30)/ 2.65    * 100
.35/2.65  * 100
13.2 % decrease
-13.2% if you need to write is as a negative
7 0
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Helpppppppppppppppppp
harkovskaia [24]

Answer:

Answer choice B

Step-by-step explanation:

When you factor the equation, 12 only has 6x2 to equal the -12x. This means that you'll factor it into (3x-6)(x-2). When you set either of these equal to 0, the x value is 2.

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Which two ratios represent quantities that are proportional
Tpy6a [65]

Answer:

Two quantities have a proportional relationship if they can be expressed in the general form y = kx, where k is the constant of proportionality. In other words, these quantities always maintain the same ratio--that is, when you divide any pair of the two values, you always get the same number k.

8 0
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Read 2 more answers
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
What is 97.356 in base ten numerals
nadya68 [22]
97.356

<span>ninety seven and three hundred fifty six <span>thousandths</span></span>

4 0
3 years ago
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