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2 years ago

A student, taking a true- false test, randomly guesses at every one

Mathematics

2 answers:

Ann [662]2 years ago

7 0

Answer:

Step-by-step explanation:

Each question has 2 possible sets of answers, so multiply the number of possible answers by how many answers there is and you get 32.

avanturin [10]2 years ago

5 0

Answer:

the student can choose only true

the student can choose false

the student can choose true and false at the same time

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What is the error shown above in the picture

bixtya [17]

The error is that -2 times -5 is 10 not -10. Then carry on from there because that error meant the rest is wrong as well.

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4 years ago

The circumference of Earth is 40,075 kilometers. What would be a reasonable estimate for the circumference of Earth?

Illusion [34]

40,075 kilometers?

If you're going for a very rough estimate without knowing that the circumference is 40,075, I'd say to go for 40,000 but I'm not really sure what you're asking.

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3 years ago

A young college student puts $2,500 in savings into a special bank account. The account earns interest at a rate of 3%, compound

Serggg [28]

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3 years ago

Evaluate each expression.

KonstantinChe [14]

Answer:

Please check the explanation.

Step-by-step explanation:

Solving the expressions

given the expression

$\left(-7\right)+\:\left(-10\right)\:-\:5\:+2$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a$

$=\left(-7\right)-10-5+2$

$=-17-5+2$

$=-22+2$

$=-20$

$\left(-9\right)+4+\left(-8\right)-\left(-7\right)$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a$

$=-5+\left(-8\right)-\left(-7\right)$

$=-5-8-\left(-7\right)$

$=-13-\left(-7\right)$

$=-13+7$

$=-6$

$\left(-6\right)\:-\:\left(2\:\times \:4\right)\:-\:\left(-1\right)\:$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\left(-6\right)-\left(2\times \:4\right)-\left(-1\right)$

Calculate within parentheses

$=\left(-6\right)-8-\left(-1\right)$

$=-14-\left(-1\right)$

$=-14+1$

$=-13$

10)

$\left(-8\right)\:+\:\left(-4\:\div \:-4\right)\:-\:8$

solving

$\left(-8\right)+\left(-\frac{4}{-4}\right)-8$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-8-\frac{4}{-4}-8$

$=-8-\left(-1\right)-8$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=-8+1-8$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+1-8=-15$

$=-15$

5 0

3 years ago

The sum of r and 45 is 79.

Liula [17]

$\huge{\boxed{r=34}}$

First, let's write this as an equation. The sum (addition) of $\bf{r}$ and $\bf{45}$ is [equal to] $\bf{79}$ .

$r+45=79$

Now, we need to get the variable by itself on one side of the equals sign. We can do this by subtracting $45$ from each side.

$\boxed{r=34}$

8 0

3 years ago

Read 2 more answers