Answer:
The end result is -1/(x + 1)
Step-by-step explanation:
In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.
x^2 + 9x + 8 = (x + 1)(x + 8)
Now that we have this factored we can take the original equation and factor a -1 out of the top.
(-1)(x + 8)/(x + 1)(x + 8)
Since there is an (x + 8) on the top and bottom, we can cancel those.
-1/(x + 1)
Answer:
Rate will be $10.68/-
Step-by-step explanation:
For 38 pieces we have price $406
For 1 piece= 406/38 = 10.68
The rate will be $10.68/-
Answer:

Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>
- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be

<h3>Case-2:</h3>
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,

<h3>Case-3:</h3>
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,

Thus our system of equations is

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

Now solve the equation accordingly:

Solving the equation for x and y yields:

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437
Answer:
5:15; 5 cups of juice and 15 cups of lemonade
Step-by-step explanation:
when simplified, the ratio is 1:3; so the first number multiplied by 3 equals the 2nd number
other answers: 6:18, 7:21, 8:24
Answer:
Associative
Step-by-step explanation:
When three or more numbers are multiplied, the product is the same regardless of the way in which the numbers are grouped.