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2 years ago

14

How much will a one time investment of $250 be when invested at 6% for 40 years and compounded annually. Round your answer to th

e nearest cent (2 decimal places). You will not be able to bypass this question until you have the correct answer. Do not use commas in your answer.

1 answer:

anzhelika [568]2 years ago

7 0

Answer:

$2571.43

Step-by-step explanation:

F = P(1 + r)^t

F = 250(1 + 0.06)^40

F = 2571.43

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Number 24 ion know the answer

Stels [109]

Answer:

C.620

Step-by-step explanation:

125+185=310

31082=620

8 0

3 years ago

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I need help with these questions ( see image for question ).<br>Please show working.<br>

antiseptic1488 [7]

Answer:

k = -4 ± 2√5

Step-by-step explanation:

#22

<h3>Given </h3>

Equation x² -4x + 1 = k(x - 4) with equal roots

<h3>To find</h3>

The value of k

<h3>Solution</h3>

<u>The equation in standard form is:</u>

x² -4x + 1 = k(x - 4)
x² - 4x - kx + 1 + 4 = 0
x² - (k + 4)x + 5 = 0

<u>When the quadratic equation has equal roots its discriminant is zero</u>

D = 0
b² - 4ac = 0
(k + 4)² - 4*5 = 0
(k + 4)² = 20
k + 4 = ± √20
k = - 4 ± √20
or
k = -4 ± 2√5

5 0

3 years ago

NEED HELP NOW!!!!!!!

Bad White [126]

Answer a = 5 and b = 2.

Procedure

Initially means x = 0, then

5 = a*b^0 = a*1 = a, then a = 5

When x = 1, the height is the double of 5, i.e 10 and

10 = a.b^1 = a.b ⇒ b = 10/a = 10/5 = 2

The a = 5 and b = 2, so the equation is y =5(2)^x

7 0

3 years ago

The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle

Gekata [30.6K]

Answer:

t = 42857.14 h

Step-by-step explanation:

Given that,

The speed of space shuttle, v = 28000 km/h

We know that, the distance between the Saturn and the Earth is 1,200,000,000 km.

Let t be the time.

As we know, speed = distance/time

So,

$t=\dfrac{d}{v}\\\\t=\dfrac{1,200,000,000}{28000}\\\\t=42857.14\ h$

So, the required time is equal to 42857.14 hours.

6 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors $\vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a).$ These vectors are collinear, then

$\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.$

Answer 5: $-\dfrac{a}{b}=-\dfrac{d}{c}.$

5 0

4 years ago

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