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3 years ago

NEED HELP NOW!!!!!!!

1 answer:

7 0

Answer a = 5 and b = 2.

Procedure

Initially means x = 0, then

5 = a*b^0 = a*1 = a, then a = 5

When x = 1, the height is the double of 5, i.e 10 and

10 = a.b^1 = a.b ⇒ b = 10/a = 10/5 = 2

The a = 5 and b = 2, so the equation is y =5(2)^x

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Answer:

domain:

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range:

$( - \infty ,4]$

equation:

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Step-by-step explanation:

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babunello [35]

The x-coordinate of the given endpoint will be " $x = 4 \pm 2\sqrt{29}$ ".

According to the question,

The end points are:

$(x_1,y_1) = (4,-1)$
$(x_2, y_2) = (x,9)$

Distance,

$6\sqrt{6}$

As we know,

The distance formula,

→ $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By substituting the values, we get

→ $6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}$

→ $216= (x-4)^2+100$

→ $(x-4)^2 = 116$

→ $x-4 = \pm \sqrt{116}$

→ $x-4=\pm 2\sqrt{29}$

→ $x = 4 \pm 2\sqrt{29}$

Thus the above answer is right.

Learn more:

brainly.com/question/18310956

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