All categories

2 years ago

Someone please help me with Graph!!

Mathematics

1 answer:

balandron [24]2 years ago

4 0

See below for the solution to the systems of equations

<h3>How to solve the systems of equations?</h3>

<u>System of equations 1</u>

Here, we have

y = -5x/3 + 3

y = x/3 -3

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, the point of intersection of the equations is (3, -2)

Hence, the solution to the system is (3, -2)

<u>System of equations 2</u>

Here, we have

y = 4x + 3

y = -x -2

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, the point of intersection of the equations is (-1, -1)

Hence, the solution to the system is (-1, -1)

Read more about system of equations at:

brainly.com/question/14323743

#SPJ1

You might be interested in

Let $a$ and $b$ be nonzero real numbers such that

algol [13]

<h3>Answer: -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0

1 year ago

Pleaseeee help!!

kkurt [141]

Answer:

answer is A. cosine

Step-by-step explanation:

8 0

3 years ago

Separated by or signs

Mademuasel [1]

Answer:

4242

Step-by-step explanation:

car is the best

3 0

3 years ago

Read 2 more answers

Please help me!<br> [One Step Inequalities]

I am Lyosha [343]

I think ur answer B.) srry if wrong .

Also i have something important to say.

(You may or may not heard of it.)

Feluka,Iahivintha an other username are posting links that give you viruses. DON'T TRUST LINKS.

THIS is the link an there is a new one PLEASE DON'T CLICK IT c utt.ly/nz6 VGda and is.gd/ qKzp BU

There more and more people doing this.

If you see this link don't click it. IT will send a virus and download bad stuff on your device. Please repost so people wont fall for it. Have a good day or night. <3

3 0

3 years ago

3 times (-8) times (-2)

dexar [7]

Answer:

Step-by-step explanation:

Signals during a multiplication of two numbers:

They have the same signal: The multiplication is positive.

They have different signals: The multiplication is negative.

3 times (-8) times (-2)

First 3*(-8):

Different signals, so negative. 3*8 = 24. So the answer is -24.

Then:

3*(-8)*(-2) = (-24)*(-2)

Same signal, so positive. 24*2 = 48. The answer is 48.

4 0

2 years ago