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Anastaziya [24]
3 years ago
9

Me compro un Frigorífico de 352,1 w de potencia, si la conecto a la red de 240 voltios. ¿Que intensidad de corriente (Amperios)

demandará funcionando al máximo?
Mathematics
1 answer:
Tems11 [23]3 years ago
8 0

Answer:

the answer is c

Step-by-step explanation:

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HELP ME PLEASE!! look at screenshot!! (10 pts)
ivolga24 [154]

Answer:

C) 72 square yards

Step-by-step explanation:

I cut it into two shapes. One being the rectangle on top with values 12 yd and 3 yd. the other being the square 6yd by 6yd

12•3= 36

6•6= 36

36+36= 72

72 square yards

hope this helps chu luv <3

5 0
3 years ago
Use this graph and the shapes shown to complete the tasks in this activity.
Kruka [31]

Answer: A reelection across the Y axis, then a reflection across the X axis.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Helppppp !!!!!! <br><br>8^6 ÷ 8^7<br><br>A. 8^0<br>B. 8^1 <br>C. 8^5<br>D. 8^-1<br>E. 8^10​
MArishka [77]

8^6 ÷ 8^7 = 8^{6-7} = 8^{-1}

<h3>CMIIW</h3>
3 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!! SPAM ANSWERS WILL BE REPORTED. I REALLY APPRECIATE IT
Advocard [28]

i think it's linear -2, y intercept = 35. it's like 35 every 2 minutes, i think I might be wrong sorry

4 0
3 years ago
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