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2 years ago

Simplify the exponential expression.

Mathematics

1 answer:

USPshnik [31]2 years ago

6 0

Answer:

$\dfrac{1}{j^8}$

Step-by-step explanation:

$(j^2)^{-4} = j^{2 \times (-4)} = j^{-8} = \dfrac{1}{j^8}$

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2) Find each angle measure to the nearest degree

UNO [17]

Answer: AB=7.74in.;m<A

=57*;m<B=33*

Step-by-step explanation

this symbol means degrees *

8 0

2 years ago

Suppose that x is the probability that a randomly selected person is left handed. The value (1-x) is the probability that the pe

harina [27]

Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

$V(x)=1000x(1-x)$

$V(x)=1000x-1000x^2$

Differentiate the above function as shown:

$V'(x)=1000-2000x$

The double derivative of the provided function is:

$V''(x)=-2000$

To find maximum variance set first derivative equal to 0.

$1000-2000x=0$

$x=\frac{1}{2}$

The double derivative of the function at $x=\frac{1}{2}$ is less than 0.

Therefore, $x=\frac{1}{2}$ is a point of maximum.

Thus the maximum variance is:

$V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2$

$V(x)=250$

Hence, the maximum variance is 250.

4 0

3 years ago

Helppppppppppppppppppppp!

In-s [12.5K]

Answer:

1:3

Step-by-step explanation:

Since your scaling down you divide the smaller number by the larger number

7/21=1/3

=1:3

Hope this helps :)

5 0

2 years ago

10 POINTS AND BRAINLIEST! PLEASE ANSWER BOTH QUESTIONS!

jok3333 [9.3K]

Segment CF is parallel to segment BE because these segments are side by side and will have the same distance continuously between them. Therefore your answer would be,

Segment BE

∠AOF is the angle that is the supplementary angle to ∠FOD because these are two angles that sum up to 180°. hence, the answer is,

∠AOF

8 0

3 years ago

In a basketball skills competition, Corson successfully made 5 of 7 shots and Charleigh made 3 of 5

xxTIMURxx [149]

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

$=\frac{5}{7}\times 100= 71.43%$

Charleigh's percentage performance

$=\frac{3}{5}\times 100= 60%$

$\because$ Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

6 0

3 years ago