Answer:
Weakest value = 0.0196
Strongest value = 0.5929
Step-by-step explanation:
Given:
Choices
0.691
-0.14
-0.24
-0.77
Computation:
0.691² = 0.477481
-0.14² = 0.0196
-0.24² = 0.0576
-0.77² = 0.5929
Weakest value = 0.0196
Strongest value = 0.5929
Answer:
because you can show the exact points an object is at
Step-by-step explanation:
For example: A car goes x many miles in y minutes. You can easily see how many miles the car goes in y minutes.
Hope this helps!
![\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$3500\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\to &4\\ t=years\to &12 \end{cases} \\\\\\ A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%243500%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bquarterly%2C%20thus%20four%7D%0A%5Cend%7Barray%7D%5Cto%20%264%5C%5C%0At%3Dyears%5Cto%20%2612%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D3500%5Cleft%281%2B%5Cfrac%7B0.06%7D%7B4%7D%5Cright%29%5E%7B4%5Ccdot%2012%7D%5Cimplies%20A%3D3500%281.015%29%5E%7B48%7D)
so, the interest earned then will be A - 3500.
Answer:
L=10pi, or 31.42
Step-by-step explanation:
The orange one , 5/12
hope this helps! please mark brainliest :)