Time taken for hare to catch up with the tortoise will be found as follows:
time taken=distance/(relative speed)
relative speed=(speed of hare-speed of tortoise)
speed of hare=500/20=25 cm/sec
speed of tortoise=250/50=5 cm/sec
relative speed will be:
(25-5)=20 cm/ sec
thus the total time taken for hare to catch up with the tortoise will be:
1000/20
=50 sec
Answer: 50 sec
When dealing with a pool of data, the field of study is called statistics. This refers to the study of sample data and how they correlate it with the overall trend of the population. By doing this, they use terms that can best represent the sample data. These three are the most common:
1. Mean - this is the arithmetic average of the data
Mean = (<span>8+41+25+9+22+36+24+13+25+28)/10 = 23.1
2. Mode - this is the most frequent data point that can occur. In this case, the mode is 25 because it occurred twice.
3. Median - this is the middle of the sample data arranging it from least to greatest. In this case: 8, 9, 13, 22, 24, 25, 25, 28, 36, 41. The middle number is 25. Thus, the median is 25.</span>
So, we need to divide the reward into 5 parts, then award 2 parts to Jaden and 3 parts to Cadence.
$140 / 5 = $28
Jaden gets 2 * 28 = $56
Cadence gets 3 * 28 = $84
$56 + $84 = $140
Answer:
the correct answer is C.
Step-by-step explanation:
because if you do the methoes method you know that it rules out 1 and 2 after you do that its just between 3 and 4, for the caunususicon there has to be one, that is why i think its 3. hope this helps
Answer: 0.4255
Step-by-step explanation:
Given: IQ scores of adults, and those scores are normally distributed
Mean: ![\mu=100](https://tex.z-dn.net/?f=%5Cmu%3D100)
Standard deviation: ![\sigma= 15](https://tex.z-dn.net/?f=%5Csigma%3D%2015)
Let X denotes the IQ of a random adults.
The area between 102 and 130 = ![P(102](https://tex.z-dn.net/?f=P%28102%3CX%3C130%29%3DP%28%5Cdfrac%7B102-100%7D%7B15%7D%3C%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3C%5Cdfrac%7B130-100%7D%7B15%7D%29)
![=P(0.13](https://tex.z-dn.net/?f=%3DP%280.13%3CZ%3C2%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3DP%28Z%3C2%29-P%28Z%3C0.13%29%5C%5C%5C%5C%3D0.9772-%200.5517%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.4255)
Hence, area between 102 and 130 = 0.4255