All categories

2 years ago

Please Answer, No links! reporting right away!.. giving brainliest and more points!

Mathematics

1 answer:

loris [4]2 years ago

4 0

Answer:

A) 154x89 _s2

Step-by-step explanation:

A) 154x89 _s2

sA) 154x89 _s2

You might be interested in

State the properties of the Normal Probability Distribution<br> in own word.

dybincka [34]

Answer:

he mean, mode and median are all equal. The curve is symmetric at the center (i.e. around the mean, μ). Exactly half of the values are to the left of center and exactly half the values are to the right. The total area under the curve is 1.

Step-by-step explanation:

4 0

2 years ago

If Rich decides to make no payments during the 4.5 years, the interest will be capitalized at the end of that period. a. what wi

Setler79 [48]

Answer:

a. $9,425.10

b. $3,707.60

Step-by-step explanation:

5 0

3 years ago

What’s the area of a circle to the nearest square foot with the radius of 7000 use 3.14 for pie

yawa3891 [41]

Pi*r^2
3.14*7000^2
153,860,000

7 0

2 years ago

a 24 ft ladder is leaning against a 20 ft building, what is the distance between the bottom of the ladder and the base of the bu

madreJ [45]

The distance at the base is 4 feet. Hope this helps.

4 0

2 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

1 year ago