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AnnZ [28]
1 year ago
8

Beth is going to enclose a rectangular area in back of her house. the house wall will form one of the four sides of the fenced i

n area, so beth will only need to construct three sides of fencing. beth has 48 feet of fencing. she wants to enclose the maximum possible area. what amount of fence should beth use for the side labeled x?
Mathematics
1 answer:
Alina [70]1 year ago
7 0

The maximum possible area would have a length of 24 feet and width of 12 feet.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Let x represent the length and y represent the width, hence:

Since beth has 48 ft fencing and cover 3 sides, hence:

x + 2y = 48  

x = 48 - 2y     (1)

Also:

Area (A) = xy

A = (48 - 2y)y

A = 48y - 2y²

The maximum area is at A' = 0, hence:

A' = 48 - 4y

48 - 4y = 0

y = 12 feet

x = 48 - 2(12) = 24

The maximum possible area would have a length of 24 feet and width of 12 feet.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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State whether the lines are parallel, perpendicular, coinciding, or neither: 6x+3y=–15 and y–3=–2x
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<u>Step-By-Step Explanation:</u>

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3y/3 = -6x/3 + 15/3

y = -2x + 5

<u>We can see that the slope of 6x+3y = 15 is -2</u>

Put the Function in Slope Intercept Form and Find the Slope of y–3=–2x

y–3=–2x

y = -2x + 3

Here are our two Functions In Slope Intercept Form

y = -2x + 5

y = -2x + 3

<u>Remember the m = slope and the b = y-intercept</u>

y = mx + b

y = -2x + 5

y = -2x + 3

------------------------------------------------------------------------------------------------------

We can see both equations have the same slope of -2 so this means they could be parallel because parallel functions have the same slope but coinciding functions have the same slope too. To tell if the two functions are coinciding, the functions need to have the same slope and the same y-intercept. Looking at the two functions, we can see they have the same slope of -2 but their y-intercept are different so this makes the two functions parallel.

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Hope this helped! :3
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f(x,y_1,{y_1}',{y_1}'')=0
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To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

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