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Naya [18.7K]
3 years ago
11

Find all of the polar coordinates of point P if p=(1,-pi/6)

Mathematics
2 answers:
Mama L [17]3 years ago
6 0

Answer:

The all polar coordinates of point P are  (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n).

Step-by-step explanation:

The polar coordinates can be written as (r,Ф)= (r,Ф+2nn) or (r,Ф) =(-r,Ф+(2n+1)n) and n is any integer value.

We are given p=(1,-pi/6)

P(r,Ф), then r = 1 and Ф = -pi/6

The polar coordinates will be

P(r,Ф)= (r,Ф+2nn)  = (1 , -pi/6 + 2nn) and n is any positive integer and the value of r is positive.

P(r,Ф) =(-r,Ф+(2n+1)n) = (-1, -pi/6+(2n+1)n) and n is any positive integer and the value of r is negative.

The all polar coordinates of point P are  (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n)

DerKrebs [107]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Just took the test on Edge 2020

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Read 2 more answers
Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?
Marina86 [1]

Answer:

The inverse of 2(x - 2)^2 = 8(7 + y) is y=\sqrt{(4x+28)}+2

Step-by-step explanation:

Given equation :2(x - 2)^2 = 8(7 + y)

\Rightarrow \frac{2(x-2)^2}{8}=7+y\\\Rightarrow \frac{2(x-2)^2}{8}-7=y

Replace x with y and y with x

So, \Rightarrow \frac{2(y-2)^2}{8}-7=x\\\Rightarrow \frac{2(y-2)^2}{8}=x+7\\\Rightarrow 2(y-2)^2=8(x+7)\\\Rightarrow (y-2)^2=4(x+7)\\\Rightarrow (y-2)=\sqrt{4(x+7)}\\\Rightarrow y=\sqrt{4(x+7)}+2\\\Rightarrow y=\sqrt{4x+28)}+2

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