All categories

3 years ago

Can somebody help me with number 7? Please explain as well! :)

Mathematics

1 answer:

gayaneshka [121]3 years ago

4 0

To factor number 7 :
3x^2-12
3x^2+3×-4
3*1, -4:2*-2
3(x^2-2^2)
use difference of square formula ((a^2+b^2=(a+b)(a-b))
3(x+2)(x-2)

You might be interested in

Find the H.C.F of the following expressions.

Art [367]

Step-by-step explanation:

Hey there!

Please look your required answer in pictures.

Hope it helps!

5 0

3 years ago

Factorise- 6y-15y^2 HELP

Citrus2011 [14]

We will take the common terms in the expressions-

Here in the expression, 3y is a common term.
So,

$6y - 15y^{2}$

$3y(2 - 5y)$

So, the answer is $3y(2 -5y)$

7 0

3 years ago

Read 2 more answers

93000000 in standard form

noname [10]

It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)

3 0

3 years ago

How do you simplify 8x over 45

Hitman42 [59]

x over 5 becuase the top and bottom are both divisible by 8 so you do that.

3 0

3 years ago

Read 2 more answers

A company estimates that it will sell ????(x) units of a product after spending x thousand dollars on advertising, as given by ?

zepelin [54]

Answer:

$(11\frac{1}{3},20)$

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

$N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40$

$N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}$

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

$N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600$

Thus, the rate of change of sales $N'(x)$ is increasing in the interval $(11\frac{1}{3},20)$ on 10≤x≤40.

7 0

3 years ago