Answer:
D:y+9=-4(x-4)
Step-by-step explanation:
The positive 9 comes from the top of the graph and its -4 because its on the lower half of the graph.
He will never reach the full foot, this is because if he travels 1/2 of the distance of the previous jump each time there will always be a fraction that is unaccounted for.
Angle 2 is 143
angle 4 is 37
angle 7 is 143
angle 8 is 37
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{
}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
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Answer:
The number of ways to form different groups of four subjects is 4845.
Step-by-step explanation:
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

In this case, 4 subjects are randomly selected from a group of 20 subjects.
Compute the number of ways to form different groups of four subjects as follows:



Thus, the number of ways to form different groups of four subjects is 4845.