What is 3k-14=3(k-5)+1 ?
1 answer:
You might be interested in
Answer:
The cars are 10702ft apart
Step-by-step explanation:
Height of the plane from the high way = 5150ft
Considering Triangle ABD, we will be using SOHCAHTOA
Tan = Opposite/ Adjacent
Tan 54° = Y/5150
Y = 5150*tan54°
Y = 7088 ft
Considering Triangle ADC, Tan = Opposite/ Adjacent is also applicable
Tan 34° = X/5150
X = 5150*tan 54°
X = 3614ft
The distance between the two cars = (X+Y)
= 7088 + 3614
= 10702ft
4. You're right that the leg labeled 
occurs in a 1-to-2 ratio with the hypotenuse, but more to the point, it also occurs with the leg of length 10 in a 1-to-
ratio. In other words,
and so
5. In this kind of triangle, the legs form a 1-to-
ratio with the hypotenuse, so it follows that 
.
6. You have and 
mismatched. The larger leg in this kind of triangle has the scaling factor. So in fact, 
, which makes the larger leg 
, and the hypotenuse would be 
.
and so
5. In this kind of triangle, the legs form a 1-to-
6. You have