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3 years ago

What is 3k-14=3(k-5)+1 ?

Mathematics

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

True

Step-by-step explanation:

3k-14=3(k-5)+1

3k-14=3k-15+1

3k-3k=14-15+1

0=14-15+1

-14=-15+1

-14=-14

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A ratio compares the relative sizes of ______ quantities .

Andre45 [30]

Answer:

two

Step-by-step explanation:

A ratio compares the relative sizes of two quantities .

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3 years ago

There are 24 hours in a day, At 7 a.m. how many hours are left in the day?

mariarad [96]

Answer:

Step-by-step explanation:

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3 years ago

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Math Questions :3 thank uu <3

coldgirl [10]

14. 1.5, 10 <- Answer
15. 5,1 <- Answer

Proof 14

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5
y = 10

Proof 15.

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 5 y = 1

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3 years ago

Hi. I need help with these questions (see image) Please show workings.

pantera1 [17]

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

$\frac{dy}{dx}$ = f'(g(x)) × g'(x) ← chain rule

and the standard derivatives

$\frac{d}{dx}$ ( $log_{a}$ x ) = $\frac{1}{xlna}$ , $\frac{d}{dx}$ (lnx) = $\frac{1}{x}$

(a)

Given

y = $log_{a}$ $\sqrt{(1+x)}$

$\frac{dy}{dx}$ = $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{d}{dx}$ ( $(1+x)^{\frac{1}{2} }$

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2}$ $(1+x)^{-\frac{1}{2} }$ × $\frac{d}{dx}$ (1 + x)

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2\sqrt{(1+x)} }$ × 1

= $\frac{1}{2lna(1+x)}$

= $\frac{1}{(1+x)lna^2}$

(b)

Given

y = ln sinx

$\frac{dy}{dx}$ = $\frac{1}{sinx}$ × $\frac{d}{dx}$ (sinx)

= $\frac{1}{sinx}$ × cosx

= $\frac{cosx}{sinx}$

= cotx

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3 years ago

Find the missing side or angle.

alexandr402 [8]

Answer: a = [ 65.8]

Step-by-step explanation:

A = 18°

B = 28°

b = 100

a = [ x ]

$\dfrac{100}{sin \: 28^{o} } =\dfrac{x}{sin \: 18^{o} } \\\\\dfrac{100}{0.4694715628} =\dfrac{x}{0.3090169944} \\\\x=\dfrac{0.3090169944 \cdot 100}{0.469715628} \\\\x=65.78810\dots \\x \approx 65.8$

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3 years ago

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