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Veronika [31]
2 years ago
11

IV In the xy-coordinate system above , line (not shown ) does not contain points in either quadrant or quadrant IV . Which of th

e following could be the equation of line/ ?
Mathematics
1 answer:
erik [133]2 years ago
5 0

The equation of the line could be given by: y = 3x.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, the lines goes only through quadrants III and I, which means that:

  • The line is increasing, which means that the slope is of m > 0.
  • The y-intercept is of b = 0.

Hence, researching the options on the internet, the line is:

y = 3x.

More can be learned about linear equations at brainly.com/question/24808124

#SPJ1

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Use the identity below to complete the tasks:
Gennadij [26K]

Answer:

a3+b3=(a+b)(a2-ab+b2)

4 0
3 years ago
The least common multiple of two numbers is 3780, and the greatest common divisor is 18. given that one of the numbers is 180, w
garri49 [273]
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes: 
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5 
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have. 
So, B = 2*3*3*3*7 = 378.</span>
8 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
40% of a nurse 's time is spent dispensing medicine to patients. If 16 hours per a week is spent dispending medicine, how many h
GarryVolchara [31]

Answer:

40

Step-by-step explanation:

16/.4=40

7 0
3 years ago
its back to school time and fred wants to buy sneakers. the sneakers cost $57 and he has 52.80$ in the bank. he also has seven q
Andrew [12]

$1.78 is your answer

5 0
3 years ago
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