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aleksandrvk [35]

3 years ago

9

Giovanna and Janet have jobs where they get paid by the hour .Below are the numbers of hours of each have worked on each of the

last 5 days and the amount of money they made . Which of these statements is true based on the given information?

1 answer:

Harman [31]3 years ago

5 0

I would need more information to help you. Like the numbers of hours worked, amount of money made, and the statements.

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If he pays $46.80 for one year. He receives one magazine each month for 12 months. Find the dollars he pays for each

pochemuha

Answer:

Each magazine costs 3.90

Step-by-step explanation:

Take the total cost and divide by the number of magazines

46.80/12

3.90

6 0

3 years ago

Read 2 more answers

Solve the equation −2w+4=−12. URGENT Solution

VMariaS [17]

Answer:

The solution is w=8

Step-by-step explanation:

we have

-2w+4=-12

Solve for w

That means -----> isolate the variable w

Subtract 4 both sides

-2w+4-4=-12-4

-2w=-16

Divide by -2 both sides

-2w/-2=-16/-2

w=8

7 0

3 years ago

Is this right ? Im honestly confused

fgiga [73]

Answer:

In step by step

Step-by-step explanation:

For #1, everything is perfect.

For #2, you wrote your functions out incorrectly, but your x input and y output are correct

#3 is a little messed up.

Your function is f(x)=-3x+1. Your given x's are -3, -1, 0, 1, 2, and 3. Plug all of these in.

1. f(-3)=-3(-3)+1

f(-3)=9+1
f(-3)=1

2. f(-1)=-3(-1)+1

f(-1)=3+1
f(-1)=4

3. f(0)=-3(0)+1

f(0)=0+1
f(0)=1

4. f(1)=-3(1)+1

f(1)=-3+1
f(1)=-3

5. f(2)=-3(2)+1

f(2)=-6+1
f(2)=-5

3 0

2 years ago

What is the solution set of [1/x-2]<-2

BigorU [14]

Answer:

3/2 < x < 2

Step-by-step explanation:

We assume the problem is ...

[tek]\dfrac{1}{x-2}<-2[/tex]

This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...

1 > -2(x -2)

1 > -2x +4

2x > 3 . . . . . . add 2x-1

x > 3/2

From above, we also have x < 2, so the solution set is ...

3/2 < x < 2

7 0

3 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago