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Luda [366]
2 years ago
12

Study island surface area

Mathematics
1 answer:
Anna007 [38]2 years ago
8 0

Answer:

C. 206 unit^2.

Step-by-step explanation:

Area = 2*11*5 + 2*11*3 + 2*3*5

         = 110 + 66 + 30

         =  206.

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Find the value of y if M is the midpoint of LN. 9y - 4 6y + 5 N ​ help plz
AURORKA [14]

Answer:

If M is the midpoint, then LM = MN

3x - 2= 2x +1

x = 3

So LM = 3x - 2 = 9 -2 = 7

LM = 7

8 0
4 years ago
Subtact: (9x + 5) - (4x + 3)​
jek_recluse [69]

Answer:

5x+2

Step-by-step explanation:

(9x+5)-(4x+3)

5x+2

8 0
3 years ago
A basket contains 15/16 pound of oranges .One serving of oranges is 1/8 of a pound.How many servings of oranges are there
nasty-shy [4]

Answer:

2/15 servings

Step-by-step explanation:

IF a basket contains 15/16 pound of oranges, then;

1 servings= 15/16 pounds of oranges

To get the number of servings for 1/8 pounds

x servings = 1/8 pounds

Divide both expressions

1/x = (15/16)/(1/8)

1/x = 15/16 * 8/1

1/x = 15/2

x = 2/15

Hence there will be 2/15 servings of oranges

7 0
3 years ago
Which three of the following expenses can student aid cover? tuition television school supplies parties and socializing boarding
Hitman42 [59]

The tuition, school supplies, and boarding/housing for the expenses can student aid cover.

<h3>What is decision-making?</h3>

The process of making choice is by identifying the correct decision, gathering information, and assessing alternative solutions.

The following expenses can student aid cover.

A.  Tuition - A student aid cover can be utilized to promote the tuition.

B.  Television - There is no use of the student aid cover for selling the TV.

C.  School supplies - We can use the face of the topper on the school supplies to promote schooling.

D.  Parties and socializing - There is no need for student aid cover for parties and socializing.

E.  Boarding or housing - We can use student aid cover to promote the hostel for the student.

More about the decision-making link is given below.

brainly.com/question/3369578

5 0
2 years ago
Find the zeroes of the following equation:
weqwewe [10]

Answer:  \bold{x=\dfrac{1\pm \sqrt5}{2}}

                both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}

7 0
3 years ago
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