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3 years ago

The teacher recommends that students read for

Mathematics

2 answers:

bogdanovich [222]3 years ago

6 0

Aprox 12. On Average, you can read 20 pages in 30 minutes and divide 20 by 30 you get 0.6 and 0.6 x 20 is 12.

lana [24]3 years ago

5 0

Answer: There is no exact answer. Students read at different rates; books, magazines and web pages have different numbers of words per page and levels of difficulty.

Step-by-step explanation: You would need some average rate for the class. Or conduct a survey to ask students how many pages they read in 20 minutes. Or design and experiment to determine students' reading rates and control the type of book and level of difficulty.

You might be interested in

Which of these figures have lines of symmetry? If so, how many?

UkoKoshka [18]

Answer:

1, 4, 0

Step-by-step explanation:

the way you did it was just right, the arrow can only be split 1 time with equal sides. The hexagon can be split 4 times with equal sides. But the lighting strike cannot be split with equal sides symmetry.

mark brainliest if helped :D

8 0

3 years ago

How do u slove this for y intercept? (4, 1); slope=3/2

Valentin [98]

Answer:

y-intercept=-5

Step-by-step explanation:

y=mx+b m/slope=3/2 the point is (x,y)/(4,1)

1=3/2(4)+b

1=12/2+b

1=6+b

-6-6

-5=b

8 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let X denote the heights of women in the USA.

It is provided that X follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

3.5.1

HACTEHA [7]

Answer:

64 degrees

Step-by-step explanation:

-add 94 and 22 together (116)

-subtract 116 from 180 (64)

4 0

3 years ago

Henry sends his hawk with a message to his uncle. The hawk flies out against the wind and returns with the wind, spending 3 hour

siniylev [52]

Answer:

Distance between Henry and his uncle is 74.25km.

Step-by-step explanation:

Speed of Hawk with wind = 50+5

=55km/hr

Speed of Hawk against wind = 50-5

=45km/hr

we know that ,

$Distance = speed \times time$

Let the distance between Henry and uncle is d,

According to the question ,

$\frac{d}{55} + \frac{d}{45} = 3$

$\frac{9d + 11d}{495} =3$

$20d = 3\times 495$

$d =\frac{3\times495}{20}$

d= 74.25km

Hence , the answer is 74.25km

5 0

4 years ago