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Likurg_2 [28]
3 years ago
15

Find such a coefficient for a for the linear equation ax-y=4, so that the graph of the equation would pass through the point M(3

,5). Build the graph of this equation
PLSSS I REALLY NEED HELP!!!
Mathematics
1 answer:
Alla [95]3 years ago
5 0

Answer:

Can you send me a picture I am confused

Step-by-step explanation:

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Simplify each expression. Write your answers in exponential notation.
GenaCL600 [577]

\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{36b^3}{9a^5} \right)^3\implies \left( \cfrac{4b^3}{a^5} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left(\cfrac{4^3b^{3\cdot 3}}{a^{5\cdot 3}}\right)}\implies \cfrac{64b^9}{a^{15}}

3 0
3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
Software - Infinite Algebra 2 Absolute Value Inequalities Solve each inequality and graph its solution. Name Sarmant Date 3/8/20
gulaghasi [49]
|6+9x|\le24

this is the correct way to solve these types of exercises

then we will try to do the same where a is (6+9x) and b is 24

|6+9x|\le24\longrightarrow-24\le6+9x\le24

and solve the right inequality for x

-24\le6+9x\le24

subtract 6 for all expression

\begin{gathered} -24-6\le6-6+9x\le24-6 \\ -30\le9x\le18 \end{gathered}

now divide on 9

\begin{gathered} -\frac{30}{9}\le\frac{9x}{9}\le\frac{18}{9} \\  \\ -\frac{10}{3}\le x\le2 \end{gathered}

ok, this means that the x values ​​will be from -10/3 to 2 including these

Graph

solution is the red zone

6 0
1 year ago
Solve for x.<br><br>x = ___<br><br>27<br>33<br>30​
kirill [66]
The answer is Answer 30 i think
4 0
3 years ago
Read 2 more answers
Is (1, 1) a solution to 3y=2x+1
Snowcat [4.5K]
Yes.
3y=2x +1
3 (1) = 2 (1) +1
(3,3)
(1,1) is a solution
3 0
3 years ago
Read 2 more answers
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