Find such a coefficient for a for the linear equation ax-y=4, so that the graph of the equation would pass through the point M(3
1 answer:
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2) Period = 3π,
2π/b = 3π, b = 2π/3π = 2/3
Amplitude = 2
Midline = 1
Equation: f(x) = 3sin(2/3(x)) + 1 (no vertical shift)
See attachment for graph.
3) f(x) = -23sin(4x) + 14,
a) amplitude = 23
b) midline = 14
c) Maximum = 37
d) Minimum = -9
Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,