Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
Answer:
a. 0.5 grams b. 0.25
Explanation:
Just use the half-life formula(I linked it below)
a. 4(1/2)^90/30=1/2
b. 4(1/2)^120/30=1/4
When insulin is deficient , GLUT4 transporters are not inserted into the cell membranes , glucose is not transported into the cells and the blood glucose concentration increases.
Insulin deficiency provides more amino acid and glycerol substrates for glucose synthesis ie increased gluconeogenesis .
With a deficiency of insulin, there is both increased hepatic glucose production through increased glycogenolysis and gluconeogenesis as well as decreased glucose use. The result is hyperglycemia.
To know more about insulin deficiency here
brainly.com/question/12978381
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Answer:
<h3>
BMI (IMC): 25.7 </h3>
<u>Explanation:</u>
Dado que el IMC de Laura es 25,7, tiene sobrepeso.
El sobrepeso puede aumentar el riesgo de ciertas afecciones de salud, incluidas las enfermedades cardiovasculares, la presión arterial alta y la diabetes tipo 2.