<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
Answer:
1548 lb
Step-by-step explanation:
Let the truck's weight be w.
Then (1/3)w = 516 lb
Solve for the truck's weight by multiplying both sides of this equation by 3:
w = 1548 lb (Answer B)
Answer:
1 1/2= 0.50
2 square root of 2= 1.41
3 3/2 1.5
4 square root of 9= 3
5 square root of 12= 3.464
6 3.56
7 4.03
8 square root of 17= 4.123
9 4.2
10 12
if I get any wrong I'm sorry have a nice day!!
Step-by-step explanation:
Answer:
I think the answer is 21
Step-by-step explanation:
The answer is 21 because we can simple reduce 26/39 = 2/3. And now that you have done that all we need to do is find what 14/w = 2/3 this is quite simple as we just have to mutiply the 3*7 to get 21 as your answer. I don't know if this is correct or not but this is my best answer.
Firstly , we will check continuity at x=1
we can use method
Suppose, f(x) is continuous at x=c
then it must satisfy
firstly , we can find limit
so, we get
now, we can find f(1)
so, we got
so, this is continuous at x=1
Hence , option-D...........................Answer
