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kherson [118]
3 years ago
8

Which equation in slope intercept represents the line that goes through the points (-1, 6) and (1, -2)

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

D) y=-4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-6)/(1-(-1))

m=-8/(1+1)

m=-8/2

m=-4

y-y1=m(x-x1)

y-6=-4(x-(-1))

y-6=-4(x+1)

y=-4x-4+6

y=-4x+2

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The City Transit Authority plans to hire 12 new bus drivers. From a group of 100 qualified applicants, of whom 65 are men and 35
QveST [7]

Answer:

1. About 1/5 chance that Mary is chosen

About 1/7 chance John is chosen

2. about 0.0286 chance mary is chosen

about  0.0154 chance john is chosen

same as answer 2

Step-by-step explanation:

1.  If you do proportions, a female's chance comes to 1/5 and a male's chance comes to 1/7.

2. for females, do 1/35  and males do 1/65

same as answer 2

4 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
What is the sign of the product (−4)(2)(−3)(6)?
lana [24]

Answer:

The sign would be positive.

The answer would be 144.

Step-by-step explanation:

Note that there are two negative numbers and two positive numbers:

positive x positive = positive answer.

negative x negative = positive answer.

Solve:

(-4) * (-3) = 12

2 * 6 = 12

12 * 12 = 144

144 would be your answer.

~

6 0
3 years ago
Read 2 more answers
(x + 4)(2x - 1)(x-3)=0
ale4655 [162]

Answer:

2x^{3} + x^{2} - 25x + 12

Step-by-step explanation:

There are three different enclosed brackets.

First multiply two of the brackets, then multiply the third by the answer

6 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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