Simplify 3x × 2 to 6x
6x - x + 8y + 4x × 2 - 3x - 5y
Simplify 4x × 2 to 8x
6x - x + 8y + 8x - 3x - 5y
Simplify
<u>10x + 3y</u>
61 quaters
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Answer:
Area of triangle = 20√2
Step-by-step explanation:
Formula:
Area of triangle = bh/2
b - base of triangle
h - height of triangle
<u>Distance formula</u>
d = √(x₂ - x₁)² +(y₂ - y₁)²
From the figure we can see that, the given triangle is right angled triangle.
Base = AC and Height = AB
<u>To find AB and AC</u>
A(1,3), B(4,7) and C(9, -5)
AB = √(4 - 1)² +(7 - 3)² = √(3² + 4²) = 5
AC = √(9 - 1)² +(-5 - 3)² = √(8² + -8²) = 8√2
<u>To find the are of triangle</u>
Area = bh/2 = (5* 8√2)/2 = 20√2
Therefore the area of triangle = 20√2 square units
Ax - c = 2x + 5
ax - c + c = 2x + 5 + c
ax = 2x + 5 + c
ax - 2x = 2x - 2x + 5 + c
ax - 2x = c + 5
X(a - 2) = c + 5
X(a - 2)/(a - 2) = c+5/(a-2)
X = c+5/a-2
I believe this would be the solution.
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