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2 years ago

A shape has an area of 37 mm², of which 60%

Mathematics

1 answer:

levacccp [35]2 years ago

4 0

If the side are increased by 45% then the area of green part will be 26.6955 $mm^{2}$ .

Given that area of a shape of 37 $mm^{2}$ in which 60% is green.

We are required to find the area of green region if the side is increased by 45%.

Area is basically part of a surface covered by a shape.

When the side is increased by 45% then the area will increase by 45%*45%=20.25%.

Increased area =37*20.25%=7.4925

New area=37+7.4925

=44.4925

We have been given that 60% is the area of green.

Area of green region=44.4925*60/100

=26.6955 $mm^{2}$

Hence if the sides are increased by 45% then the area of green part will be 26.6955 $mm^{2}$ .

Learn more about area at brainly.com/question/25965491

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3 years ago

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Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

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