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3 years ago

Identify the type of pair of angles labeled as 1 and 2 in the figure.

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

Hey!!

1 and 2 are vertical angles.

Vertically opposite angles are always equal to each other.

Hope it helps..

d1i1m1o1n [39]3 years ago

4 0

Answer:

Step-by-step explanation:

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15 people are expected for a dinner. Three ounces of corn serves one person. A can of corn is nine ounces. How many cans of corn

timofeeve [1]

5 cans need to be bought. There are three servings in each can so you divide 15 by 3.

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3 years ago

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Solve for d: 2d+1/6=6(1/3d+1)

taurus [48]

2d+1/6=2d+6 (I distributed the 6 to what was in the parentheses)
2d-2d=6-1/6 (I subtracted 2d from both sides to get the variables on one side and 1/6 from both sides to get the variables by themselves)
0=35/6 (combined like terms)
0=35/6 is an untrue statement so x doesn't exist

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3 years ago

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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP

algol13

Answer: it think it’s the third one

Step-by-step explanation:

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2 years ago

H(x)=-x^2+6x. So what is the value of h(2)

crimeas [40]

✩ Answer:

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$\bold{Hello!}\\\bold{Your~answer~is~below!}$

✩ Step-by-step explanation:

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*

✺ Quadratic polynomials can be factored using the transformation $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ , where $x_{1}$ and $x_{2}$ are the solutions of the quadratic equation $ax^2+bx+c=0$ :

$-x^2+6x=0$

✺ All equations of the form $ax^2+bx+c=0$ can be solved using the quadratic formula:

$-b=\frac{+}\\\sqrt{b^2-4ac}\\~~~~~~~~~~~~~2a$

✺ The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction:

$x=\frac{\sqrt{-6\frac{+}\\\sqrt{6^2}}}{2(-1)}$

✺ Take the square root of $6^2$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{2(-1)}$

✺ Multiply $2$ times $-1$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is plus. Add $-6$ to $6$ :

$x=\frac{0}{-2}$

✺ Divide $0$ by $-2$ :

$x=0$

-OR-

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is minus. Subtract $6$ from $-6$ :

$x=\frac{-12}{-2}$

✺ Divide $-12$ by $-2$ :

$x=6$

✺ Optional : Factor the original expression using $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ . Substitute $0$ for $x_{1}$ and $6$ for $x_{2}$ :

$-x^2+6x=-x(x-6)$

✩ Answer:

✺ Factored Form: $x(x-6)$

✺ Exact Form: $x=6$

✺ Graph Point Form: $x=(6,0)$

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8 0

3 years ago

Paul is saving for a down payment to buy a house. The account earns 13% interest compound quarterly, and he wants to have $15,00

Tatiana [17]

Answer:

The principal must be = $8991.88

Step-by-step explanation:

Formula for compound interest is:

$A = P(1 + \frac{r}{n})^{nt}$

Where A is the amount after 't' years.

P is the principal amount

n is the number of times interest is compounded each year.

r is the rate of interest.

Here, we are given that:

Amount, A = $15000

Rate of interest = 13 % compounded quarterly i.e. 4 times every year

Number of times, interest is compounded each year, n = 4

Time, t = 4 years.

To find, Principal P = ?

Putting all the given values in the formula to find P.

$15000 = P(1 + \frac{13}{400})^{4\times 4}\\\Rightarrow 15000 = P(1 + 0.0325)^{16}\\\Rightarrow 15000 = P(1.0325)^{16} \\\Rightarrow 15000 = P \times 1.66817253\\\Rightarrow P = \dfrac{15000}{1.66817253}\\\Rightarrow P \approx \$8991.88$

So, the principal must be = $8991.88

4 0

3 years ago