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zvonat [6]
2 years ago
13

The base of a triangle is 3 more than 2 times of height. Determine the dimensions that give total area of 10 square feet.

Mathematics
1 answer:
Alona [7]2 years ago
3 0

Answer:

height = 2.5 ft , base = 8 ft

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

height = h then base = 2h + 3 and A = 10 , then

\frac{1}{2} h(h + 3) = 10 ( multiply both sides by 2 to clear the fraction )

h(h + 3) = 20 , that is

h² + 3h = 20 ( subtract 20 from both sides )

h² + 3h - 20 = 0 ← in standard form

(h + 4)(2h - 5) = 0 ← in factored form

equate each factor to zero and solve for h

h + 4 = 0 ⇒ h = - 4

2h - 5 = 0 ⇒ 2h = 5 ⇒ h = 2.5

but h > 0 , then h = 2.5

and 2h + 3 = 2(2.5) + 3 = 5 + 3 = 8

that is height = 2.5 ft and base = 8 ft

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determine if each polygons are similar, if so, write the similarity statement and the similarity ratio. if not explain why.
Delicious77 [7]

Answer:

They are not similar

Step-by-step Explanation:

For two polygons to be considered similar, two conditions must be met:

1. The ratio of their corresponding sides must be equal, and must have the same scale factor.

2. Their corresponding angles must be the same. That is, the corresponding angles must be congruent.

Now let us examine the two polygons ( ∆AYP and ∆BOX) given to ascertain if they are similar.

First, we can observe that only two of their corresponding sides were given. The third corresponding side, "YP/OX" is not given. This makes it difficult for us to tell if the polygons are similar, if we are to base our conclusion on merely considering the ratio of their corresponding sides.

Although, the two given corresponding sides (AY/BO & AP/BX), both have equal ratio ⅖, i.e. AY/BO = AP/BX = ⅖. This is not enough to tell both polygons are similar, as we cannot tell if the third corresponding side would give us same ratio, since it wasn't given in the diagram.

==>Next is to examine the interior angles of the polygons, whether the measure of their corresponding angles are the same.

Thus, from the diagram, we can see that two angles of the each triangle were given. We can find the measure of the third angle not given since we know that sum of the interior angles of a triangle = 180°

Thus, <P in ∆AYP = 180 - (90+20) = 180 - 110

<P = 70°

Thus, <B in ∆BOX = 180 - (90+80) = 180 - 170

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From the above calculation, comparing both polygons having known the measures of their corresponding angles, we can conclude that both polygons given in the question are not similar.

This is because the measure of their corresponding angles are not congruent.

<A is not congruent to <B, so likewise with <P and <X.

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3 years ago
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3 years ago
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KATRIN_1 [288]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

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The expression of interest is ...

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3 years ago
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Answer:

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Step-by-step explanation:

The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.

Both triangles are right because they have an internal angle of 90°, so the second condition is also met.

Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.

One of these two conditions should be met:

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