Answer:
Hi there.....
Step-by-step explanation:
This is ur answer......
1, 3, 5, 7, 9, 11, 13, 15.................39
Therefore the total sum = 400
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Answer:
I tried solving it and didn't get same exact numbers but I got 8.67 million people so it might be answer choice B.
<span> 7x+2y=5;13x+14y=-1 </span>Solution :<span><span> {x,y} = {1,-1}</span>
</span>System of Linear Equations entered :<span><span> [1] 7x + 2y = 5
</span><span> [2] 13x + 14y = -1
</span></span>Graphic Representation of the Equations :<span> 2y + 7x = 5 14y + 13x = -1
</span>Solve by Substitution :
// Solve equation [2] for the variable y
<span> [2] 14y = -13x - 1
[2] y = -13x/14 - 1/14</span>
// Plug this in for variable y in equation [1]
<span><span> [1] 7x + 2•(-13x/14-1/14) = 5
</span><span> [1] 36x/7 = 36/7
</span><span> [1] 36x = 36
</span></span>
// Solve equation [1] for the variable x
<span><span> [1] 36x = 36</span>
<span> [1] x = 1</span> </span>
// By now we know this much :
<span><span> x = 1</span>
<span> y = -13x/14-1/14</span></span>
<span>// Use the x value to solve for y
</span>
<span> y = -(13/14)(1)-1/14 = -1 </span>Solution :<span><span> {x,y} = {1,-1}</span>
<span>
Processing ends successfully</span></span>
Answer:
Step-by-step explanation:
one
The only really certain way of getting an odd integer is to do 2k + 1. Therefore the answer should be something like 2k+1, 2k+3, 2k + 5
The best I can do for the first one is to assume that k is odd and that the answer is k + 10, k+12, k+14, but I would ask your instructor if this is merely the best answer out of a poor lot or if the question really has no answer.
Two things should be noted.
1. k has to be odd.
2. The first choice has to give consecutive integers because what is added on is 2 3 and 4. Those numbers are consecutive.
Two
k+1, k+2, k+3. See point 2 above. k is a constant and any number. 1,2,3 are consecutive so the results are consecutive. Even if k < 0 the numbers will be consecutive.
k= - 10
k+1 = - 9
k+2 = -8
k+3 = - 7
These are consecutive.
Your first choice will give either consecutive odd or even numbers depending on what k is.
If k = even, then k+6, k+ 8, k+10 will all be even.
If k = odd then the givens will be odd.
