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Hatshy [7]
2 years ago
8

12. Will you miks the paint? Answers

Mathematics
1 answer:
wolverine [178]2 years ago
7 0

The required proportion of the blue paint is 18 liters.

Given that,
The ratio of yellow and blue colors is 2:3
The proportion of the yellow color is 12 liters.
The proportion of blue color is to be determined.

<h3>What is the Ratio?</h3>

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

Let the proportion of the blue color is x,
Now, the ratio can be given as
12 / x = 2 / 3
x = 12 * 3 / 2
x = 18

Thus, the required proportion of the blue paint is 18 liters.

Learn more about Ratio here:

brainly.com/question/13419413

#SPJ1

The question given is incomplete, a proper question could be
A paint store mixes yellow and blue paint in a ratio of 2:3 to make green paint. If they used 12 liters of yellow paint, how many liters of blue paint were used?

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Answer: REACTANGLE !!!!!!!!!!!

Step-by-step explanation:

The shape of the cross-section is a rectangle. The plane is perpendicular to the base of the rectangular prism so the shape of the cross-section is the same as the top and bottom views of the rectangular prism.

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1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1-1=0

Step-by-step explanation:

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3 years ago
the height of an airplane as it descends to an airport runway is it rational ,integers, whole ,or irrational?
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If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
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