45degrees because angles can not be negative
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,

Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio
, we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;

Thus, the cosine of angle H is 0.53
can you get a better picture of it so I can possibly find the answer.
First move the 14 over so 1/3s = 12 then do 12 divided by 1/3, that would be 36 so s=36
Hi! the answer should be 104
----
Formula: h(g(x))
1) First you want to take the -5 and plug that into the given equation for g(x)
• 2(-5)= -10
2) Next you want to take the -10 and plug it into the equation for h(x)
• (-10)²+4= 104