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maw [93]
2 years ago
14

Oliver started his banking account with $100 and is increasing the account $20 per month. which type of function does this situa

tion model?
Mathematics
1 answer:
nata0808 [166]2 years ago
3 0

Answer:

an arithmetic sequence or a linear function.

Step-by-step explanation:

<h2>Arithmetic:</h2>

he has $100 and ADDS $20 each month. in arithmetic sequences we have a value for a sub 1 in this case 100, then add the rate of change or in this case 20 times the months or d. Since this function follows the rules this is an arithmetic sequence.

<h2>Linear function:</h2>

y=mx+c

let y be the amount of money he has in his banking account,

let x be months.

let m be 20 because that is what he adds per month or per x.

let c be the starting value or 100.

y=20x+100

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Which is the area of a circle with a radius of 5 units? (use 3.14 for )?
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When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 55 bat
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The probability of accepting this shipment is 98%.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Here, we have

Almost all such shipments will be accepted because the probability of having a sample with more than 3 defective batteries is very low.

The shipment will be accepted if at most 3 batteries don't meet specifications.

This can be modeled as a binomial distribution, where the sample size is n=55 and the probability of not meeting the specifications of any battery is p=0.02.

The shipment will be accepted if D ≤ 3.

The probability of this event is:

P( D ≤ 3) = P(D=0) + P(D=1) + P(D=2) + P(D=3)

P(D=X) = n!/(x!(n-x)!) pˣ(1-p)ⁿ⁻ˣ

P(D=0) = 55!/(0!(55-0)!) 0.02⁰(1-0.02)⁵⁵⁻⁰ = 1× 1 × 0.32 = 0.32

P(D=1) = 55!/(1!(55-1)!) 0.02¹(1-0.02)⁵⁴ = 54 × 0.02 × 0.33= 0.35

P(D=2) = 55!/(2!(55-2)!) 0.02²(1-0.02)⁵³ = 55 ×27 × 0.0004 × 0.34= 0.20

P(D=3) = 55!/(3!(55-3)!) 0.02³(1-0.02)⁵² = 25740× 0.0000008 × 0.35= 0.07

Then,

P( D ≤ 3) = P(D=0) + P(D=1) + P(D=2) + P(D=3)

P( D ≤ 3) = 0.32 + 0.35 + 0.20 + 0.07

P( D ≤ 3) = 0.98

Hence, the probability of accepting this shipment is 98%.

To learn more about the probability from the given link

brainly.com/question/24756209

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