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Rashid [163]
3 years ago
10

A theatre contains 441 seats and the ticket prices for a recent play were ​$60 for adults and ​$16 for children. If the total pr

oceeds were ​$14,800 for a​ sold-out matinee, how many of each type of ticket were​ sold?
Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0
14,800=60x+16y
x+y=441
that implies y=441-x so
14,800=60x+16(441-x)
14,800=60x+16*441-16x
14,800-16*441=44x
7744=44x
x=176 kids and 441-176 adults
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4x/5 + 2/3 + 1x/5 = x
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Answer:

There are no solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4x/5+2/3+1x/5=x

4/5x+2/3+1/5x=x

(4/5x+1/5x)+(2/3)=x(Combine Like Terms)

x+23=x

x+23=x

Step 2: Subtract x from both sides.

x+2/3−x=x−x

2/3=0

Step 3: Subtract 2/3 from both sides.

2/3−2/3=0−2/3

0=−2/3

Answer:

There are no solutions.

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Answer:

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Answer:

Step-by-step explanation:

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For this problem, we have five numbers, so we add them together and divide by 5:

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