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spin [16.1K]
2 years ago
13

Tabular representations h (x) as transformations X f(x) X g(x) X h (x) for the functions f, g, and h are given below. Write g(x)

and of f (x). -3 - 2 2 2 - - 2 -1 1 1 -2 - 1 1 0 0 - 3 -1 - 3 0 -2 1 1 0 1 1 2 2 2 1 N 2 3​

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

g(x) = f(x - 1)

h(x) = f(x) + 1

Step-by-step explanation:

If you look at the values of f(x), g(x) and h(x) you will see that the for  a specific value of x in the first table, the f(x) value is the g(x) value for x + 1

For example, at x = -2, we have f(-2) = -2 in the first table

In the second table for x = -3 we have g(-3) = -2 and -3 = -2 -1 So g(-2-1) = f(-2). Looking at the other values in both tables we see that this relation holds good for all x values in the first table

The x values given for f(x) in the first table are the same as those given in the third table for h(x). We see that the h(x) value in the third table is exactly 1 + the f(x) value in the first table and this is true for all values of x in first and third tables

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Given f(x) =17 -x2 what is the average rate of change in f(x) over the interval [1,5]
Artist 52 [7]
By definition <span>the average rate of change is given by:
 </span>AVR =  \frac{f(x2) - f(x1)}{x2-x1}
 <span>We have the following function:
 </span>f(x) =17 - x^2
 We evaluate the function for the given interval:
 For X = 1:
 f(1) =17 - 1^2
 f(1) =17 - 1
 f(1) =16
 For X = 5:
 f(5) =17 - 5^2
 f(5) =17 - 25
 f(5) =-8
 Then, replacing values we have:
 AVR = \frac{-8 - 16}{5-1}
 AVR = \frac{-24}{4}
 AVR = -6
 Answer:
 <span>the average rate of change in f(x) over the interval [1,5] is:
 </span>AVR = -6


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