The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
CNBD
Step-by-step explanation:
From the diagram, we can see that:
Then by Alternate Interior Angles:
From vertical angles, we also know that:
This is all we can gather from the given image. Knowing only three pairs of angles cannot prove congruence, as proving congruence requires at least one side.
Congruence cannot be determined.
Answer:
AC =4DB
Step-by-step explanation:
D is midpoint of AB .So, AD = DB
AB = 2DB ---------- (i)
B is the midpoint of AC.So, AB = BC
AC = 2AB
= 2*2DB {FROM 1}
=4DB
Distribute the .25 to get .25x + 1 - 3 = 28
Then simplify to get .25x - 2 = 28
Move the two to the right to get .25x = 30
Then divide to leave x: 30 / .25 = 120
X = 120
We Know, speed = Distance / Time
Here, Distance = 2748 miles
Time = 6 hours
Substitute their values in to the expression,
Speed = 2748 / 6 = 458 Miles / Hour
So, the speed would be: 458 miles/hour
Hope this helps!
