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Svetradugi [14.3K]
3 years ago
9

The number of calories you burn depends on your weight. A 160​-pound person burns 237 calories during 30 minutes of tennis. Find

the number of calories that a 190​-pound person would burn during the same​ activity, assuming they burn calories at the same rate.
Mathematics
1 answer:
larisa [96]3 years ago
5 0

Answer:

A 190-pound person would burn 285 calories at the same rate.

Step-by-step explanation:

<em>Calories burn depends on the weight</em>

<em>Weight of first person = 160</em>

Calories burn for 160 pounds in 30 mins =  237

Calories burn rate for 1 pound in 30 mins = \frac{237}{160} = 1.5


<em>Calories burn for 190 Pound person would be:</em>

Weight of second person = 190

Calories burn for 190 pounds in 30 min:

As the burn rate of calories is same for the two persons:

= rate × weight

= 1.5 * 190

= 285 calories

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Y=x7<br><br><br> Please help I really confused
tigry1 [53]

Answer:

Where is the rest of the question? What is it asking?

Step-by-step explanation:

Well I guess if you want to change up the equation you can do 7 * X = Y

The * is just a multiplecation symbol if you didnt know

8 0
3 years ago
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
3 years ago
Whoever responds first will get marked Best!!!A tomato sauce recipe uses 986 ounces of crushed tomatoes About how many millilite
sergejj [24]

Answer:

B . tell me if ya need proof

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
Need help with this please
OLga [1]

Answer:

k= -2

Step-by-step explanation:

you are dividing the x by -2 each time

3 0
3 years ago
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