Question

The half-life of iron-52 is approximately 8.3 hours.How much of a 13 gram sample of iron-52 would remain after 8 hours? Round to three decimal places.

Answer 1

6.665 grams of the 13 grams remain after 8 hours.

How much of a 13 gram sample of iron-52 would remain after 8 hours?

The decay equation for the 13 grams of iron-52 is:

$N(t) = 13g*e^{(-ln(2)/8.3h)*t}}$

Where N is the amount of iron-52, and t is the time in years.

Where we used the fact that the half-life is exactly 8.3 hours.

Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:

$N(8h) = 13g*e^{(-ln(2)/8.3h)*8h}} = 6.665g$

So 6.665 grams of the 13 grams remain after 8 hours.

If you want to learn more about half-life:

brainly.com/question/11152793

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