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3 years ago

How many total terms are there in the following sequence. 7,10,13,...,391,394

Mathematics

2 answers:

nlexa [21]3 years ago

4 0

Answer: n = 130

Step-by-step explanation:

The sequence is an Arithmetic progression ( AP )

The last term of the sequence is (L) is 394 with the formula

L = a + ( n- 1 )d . From the sequence, a = 7, d ( common difference ) = 3 and L ( last term ) = 394, and n = ?

Put those values in the formula above and solve for n.

a + ( n - 1 )d = L

7 + ( n - 1 ) x 3 = 394

7 + 3n - 3 = 394

4 + 3n = 394

3n = 394 - 4

3n = 390

n = 130

NISA [10]3 years ago

3 0

The sequence is 19294 the example is how many

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