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sp2606 [1]
3 years ago
13

How many total terms are there in the following sequence. 7,10,13,...,391,394

Mathematics
2 answers:
nlexa [21]3 years ago
4 0

Answer: n = 130

Step-by-step explanation:

The sequence is an Arithmetic progression ( AP )

The last term of the sequence is (L) is 394 with the formula

L  = a + ( n- 1 )d . From the sequence, a = 7, d ( common difference ) = 3 and L ( last term ) = 394, and n = ?

Put those values in the formula above and solve for n.

  a + ( n - 1 )d =  L

  7 + ( n - 1 ) x 3  = 394

         7 + 3n - 3   = 394

             4 + 3n     = 394

                    3n     = 394 - 4

                     3n     = 390

                        n     = 130      

NISA [10]3 years ago
3 0
The sequence is 19294 the example is how many
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Look at this equation. 48 = 12x. Which value of x makes the equation true?
kherson [118]

Answer:

x= 4

Step-by-step explanation:

simple math

48/12 = x

x= 4

4 0
3 years ago
Read 2 more answers
1
cricket20 [7]

Answer:

<em>5.33 secs</em>

Step-by-step explanation:

Given the equation of the height modeled by the equation/

h(t) = -3.2 + 12.5t + 24.8

The object strikes the ground when the height h(t) is zero

Substituting h(t) = 0 into the expression

h(t) = -3.2t² + 12.5t + 24.8

0 =  -3.2t² + 12.5t + 24.8

-3.2t² + 12.5t + 24.8 = 0

Multiply through by minus sign

3.2t² - 12.5t - 24.8 = 0

From the expression a = 3.2, b = -12.5 and c = -24.8

t = -(-12.5)±√(-12.5)²-4(3.2)(-24.8)/2(3.2)

t = 12.5±√156.25+317.44)/6.4

t = 12.5±√473.69/6.42

t = 12.5±21.76/6.42

t = 12.5+21.76/6.42

t = 34.26/6.42

t = 5.33secs

<em>Hence the object strike the ground after 5.33 secs</em>

3 0
3 years ago
The ratio of the number of apple trees to the number of lemon trees in a farm is 9:5. There are 45 lemon trees in the farm. How
kvv77 [185]
81
5x9=45
9x9=81
you’re welcome
6 0
1 year ago
X2 – 5x + 6 = 0 solve.
Strike441 [17]
When you factor you get (x-2)(x-3)=0 then x=2 and x=3
4 0
3 years ago
A culture started with 4,000 bacteria. After 5 hours, it grew to 4,800 bacteria. Predict how many bacteria will be present after
eimsori [14]
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646

Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours

Hope it helps!
4 0
3 years ago
Read 2 more answers
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