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notsponge [240]
1 year ago
12

Let σ(n) be the sum of all positive divisors of the integer n and let p be any prime number.

Mathematics
1 answer:
Katen [24]1 year ago
8 0

The statement that "σ(n) < 2n holds true for all n of the form n = p²" has been proved.

Let p be any prime number, and let σ(n) be the sum of all positive divisors of the integer n.

As p is a prime number, and 2 is the smallest prime number, so, p\geq2

So, the positive divisors of the integer n are: 1,p,p².

As σ(n) represents the sum of all positive divisors of the integer n.

σ(n)=1+p+p²

In order to prove that σ(n) < 2n,for all n of the form n = p².

1+p+p²<2p²

p²-p-1>0

It is know that, p\geq2.

So, p²-p-1\geq1

Thus, σ(n) < 2n holds true for all n of the form n = p².

Learn more about prime numbers here:

brainly.com/question/145452

#SPJ1

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Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

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