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STALIN [3.7K]
3 years ago
5

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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Do male and female servers work the same number of hours? A sample of 25 female servers worked an average of 26 hours per week,
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Given that

Group   Group One     Group Two  

Mean       26.00 23.00

SD                 2.00 4.00

SEM         0.40 1.21

N                     25     11    

where group I represents female servers and group II male servers.

We have to calculate confidence interval for 90% for difference in means

The mean of Group One minus Group Two equals 3.00

df = 34  

 standard error of difference = 0.993

t critical = 2.034 for 90% df 34

Hence confid. interval at 90%

=Mean diff ±2.034 * std error of diff

= (0.98, 5.02)

5 0
3 years ago
What’s the answer to
Roman55 [17]

Hint: the sum of the angles is equal to 180 in a triangle. could you make an equation to use that?

3x+13, 7x+2, and 75 are the three angle values. They will sum up to 180.

Steps:

We set the equation to:

3x+13+7x+2+75=180

We can combine some terms

10x+90=180

Then, we isolate x

10x=90

And we divide by 10

x=9

Great! but we are not done yet. We want the measure of angle A, so we need to plug x back into the equation for angle a

3(9)+13

Multiply

27+13

Add

40

8 0
2 years ago
Triangles A C B and M Q R are shown. Sides A B and M R are congruent. Angles C A B and M R Q are 42 degrees. Angle C B A is 53 d
miss Akunina [59]

By ASA postulate it can be say that the triangle ABC and triangle MRQ are congruent

<h3>What is Angle Sum Property?</h3>

The sum of all three angles(interior) of a triangle is 180 degrees, and the exterior angle of a triangle measures the same as the sum of its two opposite interior angles.

Using Angle Sum Property, in ΔMRQ

<M + <R + <Q= 180

<M + 42 + 85 = 180

<M = 180 -42

<M= 53°

Now, In ΔMRQ and ΔABC  

<A= <R ,

<B = <M

AB = MR

Hence, By ASA criteria ΔMRQ ≅ ΔABC  

Learn more about this concept here:

brainly.com/question/3486366

#SPJ1

4 0
1 year ago
How can I solve for Y.<br> 5x+y=18
Korolek [52]
Y = -5x +18
x can be any number, y can be change due to x value

5 0
3 years ago
Read 2 more answers
Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen
Nataly_w [17]

Answer:

C. (-13, -7)

Step-by-step explanation:

The location of a point O(x, y) that divides a line AB with location A(x_1,y_1) and B(x_2,y_2) in the ratio m:n is given by:

x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7

Therefore the coordinates of point X is at (-13, -7)

6 0
3 years ago
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