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sveticcg [70]
1 year ago
5

PLEASE PLEASE PLEASE HELP ME ITS A MATH PROBLEM!!! EXPLANATIONS WELCOMED

Mathematics
2 answers:
nikdorinn [45]1 year ago
4 0

Answer:

  8

Step-by-step explanation:

The given ratios can be combined to a composite ratio using least common multiples.

<h3>Given ratios</h3>

We can identify each of the entities with a 2-letter designation:

  TT - Tumtum tree; TW - tulgey wood; BS - frumious Bandersnatch;

  ST - slithy tove; BG - borogoves; MR - mome raths; JW - Jabberwocky;

  JB - Jubjub birds.

Then the given ratios are ...

  • 20 TT : 1 TW
  • 1 TW : 1 BS
  • 5 ST : 2 BG
  • 2 MR : 1 JW
  • 2 JB : 200 TT . . . . (reduces to 1 : 100)
  • 200 MR : 1 BG
  • 5 JB : 1 ST

<h3>Composite ratios</h3>

The path from BS to JW is unique, so we can work our way there one ratio at a time. Having done this once, we can go back and do it again with the least possible multiplier.

Here, that turns out to be 125 Bandersnatches. We can combine these to the composite ratio ...

  125 BS : 125 TW : 2500 TT : 25 JB : 5 ST : 2 BG : 400 MR : 200 JW

Then the ratio of Bandersnatches to Jabberwocks is 125 : 200 = 5 : 8.

If there are 5 frumious Bandersnatches, there should be 8 Jabberwocks.

__

<em>Additional comment</em>

We know 1 JW : 2 MR and 200 MR : 1 BG. In order to get a common value of 200 MR in these ratios, we need to multiply the first by 100:

  100 JW : 200 MR : 1 BG

Next, we notice the other ratio involving BG is 2 BG : 5 ST, which means we need to multiply by 2 again:

  200 JW : 400 MR : 2 BG : 5 ST

The number of JB is 5 times the number of ST, so this extends to ...

  ... 5 ST : 25 JB

The number of TT is 100 times the number of JB, so we have ...

  ... 5 ST : 25 JB : 2500 TT

Continuing in like fashion, we get the composite ratio shown above. We originally worked this starting from BS. Reducing the JB/TT ratio from 2/200 to 1/100 helped eliminate an extra factor of 2.

adoni [48]1 year ago
3 0

Step-by-step explanation:

it's not really a math problem per se, it is more like a regular riddle with numbers.

true, everything involving numbers is essentially math, but then what will you do in life with things like earning a salary, going shopping, checking a calendar and schedules for bus, train and flights or business meetings, sharing a pizza with friends, playing computer games, ...

life is for a big part numbers and therefore math.

so, don't be afraid, just use your brain and common sense !

let's think this through (just be strict, concentrated, and follow each line literally) :

5 fr. Band. means 5 tulgey woods.

which means 20×5 = 100 tumtum trees.

as there are 2 jubjub birds in 200 tumtum trees, that means that there is 1 jubjub bird in the given 100 tumtum trees.

as there are 5 jubjub birds in 1 slithy toves, but we have only 1 bird, that means we have only 1/5 slithy toves.

there are 5 slithy toves in 2 borogoves. that means 1 slithy toves in 2/5 borogoves. and 1/5 slithy toves in 2/5 / 5 = 2/25 borogoves.

there are 200 mome raths in each borogove. and we have 2/25 borogoves. that means we have

200 × 2/25 = 400/25 = 16 mome raths.

and there are 2 mome raths per jabberwocky. we have 16 raths. how many pairs of raths does that make ?

16/2 = 8 pairs of raths = jabberwocks.

so, there should be 8 jabberwocks.

you see ? that's all that was needed. this was like a labyrinth riddle, where you need to find the way from an inside starting point to the exit without crossing a line (or wall).

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Step-by-step explanation:

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2 years ago
A rectangle has perimeter, P, length, land width, w. Which of the following represents lin
almond37 [142]

Answer:

l=\frac{P}{2}-w.

Step-by-step explanation:

The perimeter of a rectangle is the sum of it's side lengths.

A rectangle has 4 sides where it's opposite sides are congruent.

So if one side has measurement w, then there is another side that has measurement w.

If there is one side that has measurement l, then there is another side that has measurement l.

So if you add w+w+l+l you get 2w+2l.

They are giving us that the perimeter is P, so P=2w+2l.

we are being asking to solve for l.

P=2w+2l

First step: Isolate term that contains the l, so get 2l by itself first.

We are going to subtract 2w on both sides giving us:

P-2w=2l

2l=P-2w

Now that we have 2l by itself it is time to perform the last step in getting l by itself.

Second step: Divide both sides by 2.

This gives us:

l=(P-2w)/2

You may separate the fraction like so:

l=\frac{P-2w}{2}=\frac{P}{2}-\frac{2w}{2}=\frac{P}{2}-w.

I don't know your options but I have solve for l in terms of P and w

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3 years ago
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Answer: 11 party bags with 1 sticker leftover

Each bag contains 4 bubbles, 8 stickers, and 5 pencils.

<u>Step-by-step explanation:</u>

Find the GCF of 44 (bubbles), 89 (stickers), and 55 (pencils)

44: 2 x 2 x <u>11</u>

89: prime so choose 88 with 1 leftover

88: 2 x 2 x 2 x <u>11</u>

55: 5 x <u>11</u>

GCF = 11

Disregard the GCF to see how many of that item should go in each bag.

Bubbles: 2 x 2

Stickers: 2 x 2 x 2

Pencils: 5



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